1/4(X-4)+2/5(X-5)=1/5(X^2-53)

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Solution for 1/4(X-4)+2/5(X-5)=1/5(X^2-53) equation:


X in (-oo:+oo)

(1/4)*(X-4)+(2/5)*(X-5) = (1/5)*(X^2-53) // - (1/5)*(X^2-53)

(1/4)*(X-4)+(2/5)*(X-5)-((1/5)*(X^2-53)) = 0

(1/4)*(X-4)+(2/5)*(X-5)+(-1/5)*(X^2-53) = 0

1/4*(X-4)+2/5*(X-5)-1/5*(X^2-53) = 0

1/4*(X-4)+2/5*(X-5)-1/5*(X^2-53) = 0

13/20*X-1/5*X^2-3+53/5 = 0

13/20*X-1/5*X^2+38/5 = 0

13/20*X-1/5*X^2+38/5 = 0

1/5*(13/4*X-X^2+38) = 0

13/4*X-X^2+38 = 0

DELTA = (13/4)^2-(-1*4*38)

DELTA = 2601/16

DELTA > 0

X = ((2601/16)^(1/2)-13/4)/(-1*2) or X = (-(2601/16)^(1/2)-13/4)/(-1*2)

X = -19/4 or X = 8

1/5*(X+19/4)*(X-8) = 0

1/5*(X+19/4)*(X-8) = 0

( X+19/4 )

X+19/4 = 0 // - 19/4

X = -19/4

( X-8 )

X-8 = 0 // + 8

X = 8

X in { -19/4, 8 }

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